If a point is chosen inside the square, what is the probability that it will also be inside the
circle?
1

Point to be present exactly at midway between center and circumference of circle (let’s say radius = r) should lie at circumference of circle of radius r/2.

Favorable outcome = 2*pi*r/2

Total outcome = Point can be anywhere inside the circle of radius r = Area of circle = pi * r * r

Probability = (2*pi*r/2) / pi * r* r = 1/r.

Not completely sure about correctness . Waiting for comments to verify.

it should be all of them because it asks if you included all of those in your answer

explanation:

a electronegativity decreases beacuse the size of nucleus is bigger.