g If 50.0 mL of a 0.75 M acetic acid solution is titrated with 1.0 M sodium hydroxide, what is the pH after 10.0 mL of NaOH have been added

pH = 2.66

Explanation:

First we calculate the number of moles of each reactant, using the given volumes and concentrations:

We calculate how many acetic acid moles remain after the reaction:

We now calculate the molar concentration of acetic acid after the reaction:

27.5 mmol / (50.0 mL + 10.0 mL) = 0.458 M

Then we calculate [H⁺], using the following formula for weak acid solutions:

Finally we calculate the pH:

i'm not sure

explanation:

i'll try whatever you got