11. Nombra las siguientes sales: a. KCIO
m. NaBro
20
b. Hg(NO3),
c. NaBroz
d. Al_(SO2)3
e. (NH2PO4
f. Fe(103)2
g. Ca (10)
h. Cuso
i. Ca(HS),
j. Sc(H, PO2)3
k. CO(HCO3)2
1. MgH, SiOA
n. Cu(BO)
O. TI (CO3)3
p. Rb, PO
q. LICIO
r. Ga (SiO2),
s. Bes,
t. ZnHPO
u. Mn(HTeO3)2
v. Au(HSO )3
X. Li, HBO
y. Na SO

12. Formula las siguientes sales:
a. ortofosfato de germanio (ID)
b. hipoclorito de cesio
c. manganato de talio (III)
d. fosfato de hierro (III)
e. clorato de potasio
f. sulfito niqueloso
g. hiponitrito de estroncio
h nitrato de plata
i. seleniato de cadmio
j. nitrato de cobre(II)
k. yodato de rubidio
ayudenme xfavor es de quimica​

4- c, because all matter stays the same no matter what. it is still there. 5- b, because matter is known as mass. 6-c because, flammability is a chemical property. malleability is changing the shape of an object.

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.

Nonmetal are moldable and easily shaped

Ithink about 50 % of an original isotope's number of atoms remain