4. There are 1.9 moles of Oxygen gas at a pressure of 3.50 atm, and the temperature is 65°C. What is the volume of the gas? Remember that R = 0.0821 L x atm/Kx mol AND that you must convert °C to K.
Fill in the variables chart:

15.06 L

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

P = 3.50 atm

n = 1.9 moles

V = ?

T = 65°C = 65 + 273 = 338K

Using PV = nRT

V = nRT/P

V = (1.9 × 0.0821 × 338) ÷ (3.5)

V = 52.725 ÷ 3.5

V = 15.06 L