The gas left in a hairspray can is at a pressure of 121.2kPa at 25.0°C. If this can is thrown into a fire, what will be the resulting pressure if the fire reaches 2,111°C

969.6 kPa

Explanation:

Applying,

P/T = P'/T' Equation 1

Where P = Initial pressure of the gas, T = Initial temperature of the gas, P' = Final pressure of the gas, T' = Final temperature of the gas

make P' the subject of the equation

P' = PT'/T Equation 2

From the question,

Given: P = 121.2 kPa, T' = 2111°C = (273+2111) = 2384 K, T = 25°C = (273+25) K = 298 K

Substitute these values into equation 2

P' = (121.2×2384)298

P' = 969.6 kPa

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o