Chemistry, 31.05.2021 06:00 Mintfu2580
How many moles of Fe(OH), are produced when 85.0 L of iron(III)
sulfate at a concentration of 0.600 mol/L reacts with excess
NaOH?
Answers: 1
= 102 mol Fe(OH)₃Another question on Chemistry
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How many moles of Fe(OH), are produced when 85.0 L of iron(III)
sulfate at a concentration of 0.600...
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