14. What volume (mL) of water do I need to add to 425 mL of a 1.8 M KCl solution to make a 1.2 M solution?
How many moles of KCl are in the original solution
and how many moles of KCl are in the diluted solution?

212.5 mL

both the original and the diluted solution have 0.765 moles of KCl

Explanation:

c1V1 = c2V2

V2 = c1V1/c2 = (1.8 M×425 mL)/1.2 M = 637.5 mL

(637.5 - 425) mL = 212.5 mL

n = (1.8 mol/L)(0.425 L) = 0.765 moles of KCl

since it's a dilution, the diluted solution has the same number of moles as the original solution, 0.765 moles of KCl

1 a

2 d

3 a

4 c

explanation: