H=1.01 What is the molality of a solution containing 75.3 grams of KCI
dissolved in 100.0 grams of water?
K= 39
Cl = 35.45

Molality of solution=10.11 m

Explanation:

We are given that

Given mass of KCl(WB)=75.3 g

Given mass of water (WA)=100 g=100/1000=0.1 kg

1 kg=1000 g

Molar mass of H=1.01 g

Molar mass of K=39g

Molar mass of Cl=35.45 g

We have to find the molality of a solution.

Molar mass of KCl(MB)=39+35.45

Molar mass of KCl(MB) =74.45 g

Number of moles of solute (KCl)=

Number of moles of solute (KCl)=

Number of moles of solute (KCl)=1.011 moles

Molality of solution

=

Using the formula

Molality of solution=

Molality of solution=10.11 m

the answer is d.) potassium