Ksp for cadmium carbonate is 1.8 * 10-14, calculate the equilibrium solubility of cadmium carbonate in a solution at
constant pH of 11?
For H2CO3
Kal = 4.45 * 10-7
Ka2 = 4.7 * 10-11

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol