Determine the spec gravity of 500 mL alcohol if the density is 0.79g/ml

S.G = 0.79.

Explanation:

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In this case, according to the given information in the problem, it turns out possible for us to calculate the specific gravity of this alcohol by simply dividing its density, 0.79 g/mL by that of the water, 1 g/mL just as a reference for us to work with:

Thus, we plug in the densities to obtain:

Which is dimensionless as g/mL is cancelled out due to its presence on both top and bottom of the previous formula.

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