The molar mass of lithium carbonate is equal to 73.9 g/mol. Answer the following questions. 1) What mass of lithium carbonate is required to prepare 500.0 mL of a 0.250 M Li2CO3 solution

9.2375 grams of lithium carbonate is required to prepare 500.0 mL of a 0.250 M Li₂CO₃ solution.

Explanation:

Molarity is a measure of the concentration of a substance and is defined as the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

Molarity is expressed in units .

In this case:

Replacing in the definition of molarity:

Solving

0.250 M*0.5 L = number of moles of solute

0.125 = number of moles of solute

If the molar mass of lithium carbonate is equal to 73.9 g/mol, then the required mass of the compound can be calculated by:

9.2375 grams of lithium carbonate is required to prepare 500.0 mL of a 0.250 M Li₂CO₃ solution.

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.