N2H4 (I)--> N2 (g) + 2 H2(g)
2 H2(g) + O2 (g) --> 2 H20 (I)
- If you lost some of your...
N2H4 (I)--> N2 (g) + 2 H2(g)
2 H2(g) + O2 (g) --> 2 H20 (I)
- If you lost some of your hydrogen gas during your reaction and only produced 7.25 g of H2
(g) how many grams of water will you produce?
Question 2
1g = 1ml and 1 L = 1000 ml
How many liters of water will this produce?
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