What is the molarity when 25.0 g of the compound NaClO3 is placed in 85.0 mL of solution?

Molarity when 25.0 g of the compound is placed in 85.0 mL of solution is 294.12 M.

Explanation:

Given: Mass = 25.0 g

Volume  = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity is the number of moles of a substance divided by volume in liter.

Hence, molarity of given solution is calculated as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that molarity when 25.0 g of the compound is placed in 85.0 mL of solution is 294.12 M.

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