A sample of Oxygen effuses through a porous container about 2 times faster than an unknown gas. Estimate the molar mass of the unknown gas.

The molar mass of the unknown gas is 128g/mol

Explanation:

The rate of effusion of 2 different gases follows the equation:

Rate gas A / Rate gas B = √MM gas B / √MM gas A

Where rate is the speed of effusion of each gas and MM the molar mass of each gas

If gas A is oxygen and gas B the unknown:

Rate gas A / Rate gas B = 2 = √MM gas B / √32g/mol

11.134 = √MM gas B

128g/mol = MM gas B

The molar mass of the unknown gas is 128g/mol

altitude, density, pressure

air gets less dense the higher the altitude and also the air pressure is less as altitude rises.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)