How many moles of KCl are produce when 61.5 g of KClO3 are decomposed?

0.502mol

Explanation:

The balanced chemical equation of the reaction described in this question is as follows:

2KClO3 → 2KCl+ 3O2

According to the equation above, 2 moles of KClO3 will produce 2 moles of KCl.

Using mole = mass/molar mass to convert mass of KClO3 to moles

Molar mass of KClO3 = 39 + 35.5 + 16(3)

= 39 + 35.5 + 48

= 122.5g/mol

mole = 61.5 g ÷ 122.5g/mol

mole = 0.502mol

Since 2 moles of KClO3 will decompose to produce 2 moles of KCl.

0.502 mol of KClO3 will decompose to produce 0.502 × 2/2

= 0.502mol of KCl.

i dont know the answe

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.