A sample of aluminum requires 341 J of energy to raise the temperature from 18.0ºC to 55.0ºC. Calculate the mass of the aluminum sample.

10.22g

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat required (J)

m = mass of substance (g)

c = specific heat of substance (J/g°C)

∆T = change in temperature (°C)

According to the information given in this question;

Q = 341J

m = ?

∆T = 55.0ºC - 18.0ºC = 37°C

c of aluminum = 0.902J/g°C

Using Q = m × c × ∆T

341 = m × 0.902 × 37

341 = 33.374m

m = 341 ÷ 33.374

m = 10.22g

the answer is:  

line graphs show patterns in data with variables that change over time; whereas, circle graphs show data as parts out of a whole (such as out of 100%).

that's what i got you can count the number of atoms