How much energy must be absorbed by 45.0g of water to increase its temperature from 83 0°C to 303.0°C?

There will be 41382 J energy must be absorbed by 45.0g of water to increase its temperature from to .

Explanation:

Given: Mass = 45.0 g

Initial temperature =

Final temperature =

Formula used to calculate heat energy is as follows.

where,

q = heat energy

m = mass of substance

C = specific heat = (here, for water)

= initial temperature

= final temperature

Substitute the values into above formula as follows.

Thus, we can conclude that there will be 41382 J energy must be absorbed by 45.0g of water to increase its temperature from to .

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