HELP ME PLEAS its chem 1. The thermal waters of a spring have a hydronium ion (H3O+) concentration of 2.00 x 10-6 M. Calculate the pH of the water.

2. Acetic acid (CH3COOH) is one of the simplest carboxylic acids. It is an important chemical reagent and industrial chemical. Vinegar is dilute acetic acid, often produced by fermentation. The following is a reversible reaction:
CH3COOH ↔ H+ + CH3COO–
• Write the set up you would use to calculate the Ka of this reaction.
• Calculate the hydrogen ion concentration [H+] of a 0.1 M solution of acetic acid given that the dissociation constant of acetic acid is Ka = 1.8 x10–5. Work must be shown to earn credit.

3. Describe the reaction of a strong acid and a weak base. In general, what will the final pH be when the reaction between equal moles of a weak acid and a strong base is complete? Explain your answer.

The thermal waters of a spring have a hydronium ion (H3O+) concentration of 2.00 x . 2. Acetic acid (CH3COOH) is one of the simplest carboxylic acids. It is an important chemical reagent and industrial chemical.Have a hydronium ion (H3O+) concentration of 2.00 x 10-6 M. Calculate the pH of the water.

Explanation: The thermal waters of a spring have a hydronium ion (H3O+) concentration of 2.  spring have a hydronium ion (H3O+) concentration of 2.00 x 10-6 M. Calculate the pH of the water. 2. Acetic acid (CH3COOH) is one of the simplest carboxylic acids. It is an important chemical reagent and industrial chemical.

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72