Determine the percent composition of Lithium in Li3PO3 (lower case BOTH 3) Your
A. 20.866%
B. 31.037%
C. 48.097%
D. 10.080%

A. 20.866%

Explanation:

First, we calculate molar mass of Li3PO3

Molar mass of Li3PO3 = 6.9 (3) + 31 + 16(3)

= 20.7 + 31 + 48

= 99.7g/mol

To calculate the percent composition of Lithium, we say:

Mass of lithium in compound/mass of compound × 100

% composition = 20.7/99.7 × 100

= 0.208 × 100

= 20.8%.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied