Pls help me with is question.​

25cm³ = 0.025L of H2So4

Molarity of H2SO4 = 1moldm-³

Recall ... 1dm-³ = 1L

So the Molarity can also be 1mol/L

Mole = Molarity x volume in L

Mole of H2SO4 = 1mol/L x 0.025L

=0.025Moles of Sulphuric acid reacted.

From the equation of reaction

1mole of H2SO4 reacts to produce 1mole of Copper sulphate crystal

Since their Mole ratio is 1:1

It means that Since 0.025mole of H2SO4 reacted 0.025mole of CuSO4.5H2O would be produced

Nice.. OK

So we know the moles of CuSO4.5H2O produced

We can get the Mass

Recall

From

Mole=Mass/Molar Mass

Mass = Mole x Molar Mass

Molar Mass of CuSO4.5H2O = 64 + 32 + 16x4+ 5(2+16)

Mm= 250g/mol

Mass = 0.025mol x 250g/mol

= 6.25g of CuSO4.5H2O crystals Would be PRODUCED.

fe 55.85 g/mol and h2o 18.02 g/mol.