If a particular ore contains 56.3 % % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg k g of phosphorus?

34.44 kg

Explanation:

First we convert 1.00 kg of phosphorus (P) into moles, using its molar mass:

Then we convert 0.03125 kmoles of P into kmoles of Ca₃(PO₄)₂:

Now we calculate the mass of 0.0625 kmoles of Ca₃(PO₄)₂:

Finally we calculate the required mass of the ore, using the definition of content percentage:

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