The peppered moth (Biston betularia) has two forms, a white-bodied and a dark-bodied form. The table provided shows the percentage of each type moth population over several years.
Year
% of Population
% of Population
1965
12
88
1970
15
85
1975
37
63
1980
62
38
1985
77
23
The data provided on the shift in population of the peppered moth could support a claim that this population is responding to a change in the
environment. In order for this data to support that claim, what other data would be needed?
O
Data showing a steady change in the color of trees in this habitat between 1965 and 1985.
Data showing that eventually there were no more dark-bodied moths after 1985.
Data showing that in the years after 1985 the trend reversed leading to more dark moths.
Data showing that, in 1965, the two forms migrated from different habitats.

Show and image of the mixtures or write them

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.