A thermometer reads a pressure of 120 kPa at 0 ˚C. What is the temperature when the thermometer reads a pressure of 80 kPa? (Celsius + 273 = Kelvin) Use Gay Lussac's Formula to solve. 182 K 192 K 202 K 212 K

T₂ = 182 K

Explanation:

Given that,

Initial pressure, P₁ = 120 kPa  

Initial temperature, T₁ = 0˚C = 273 K

We need to find the final temperature when the pressure is 80 kPa.

We know that, Gay Lussac's Formula is :

So, the new temperature is equal to 182 K.

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.