Determine the hydronium ion concentration
in a solution that is 0.00011 M Ca(OH)2

4.5x10⁻¹¹M is the hydronium ion concentration

Explanation:

To solve this concentration we must find, as first, the molar concentration of OH-, [OH-]. With [OH-] we can find pOH, pH, and [H+], hydronium ion concentration, as follows:

[OH-]:

1mol of Ca(OH)2 contains 2 moles of OH-:

0.00011M Ca(OH)2 * (2moles OH- / 1mol Ca(OH)2) = 0.00022M OH-

pOH:

pOH = -log[OH-]

pOH = 3.658

pH:

pH = 14-pOH

pH = 10.34

[H+]:

10^-pH

c) should be the answer.