A rocket travels in a straight line at a speed of 5,000 m/s. After 60 seconds, it is 10,000 m/s. What is the rocket’s acceleration?

83.33 m/s^2

Explanation:

Acceleration is defined as the rate of change of velocity.

So if we know that at the beginning an object has a velocity V1.

And after a time T, the object has a velocity V2, then the average acceleration in that time interval can be calculated as:

A = (V2 - V1)/T

In this case, we know that the initial speed was 5,000 m/s

And after a time of 60 s, the velocity is 10,000 m/s

Then we have:

V1 = 5,000 m/s

T = 60s

V2 = 10,000 m/s

Then the average acceleration is:

A = (10,000 m/s - 5,000 m/s)/60s = 83.33 m/s^2

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