You are given solid CuSO4 in the lab and you are required to prepare a 250 mL of 1.0 M solution to be used in a chemical reaction. Describe in detail how you would go about preparing this solution. Clearly show how you would calculate the mass of CuSO4 that is required to prepare the solution, choice of equipment’s and glassware’s and the procedure

pointeu jusyeoseo gamsahabnida

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"