What would be the pressure, in atm, exerted by 3.2 moles of oxygen with a volume of 12.3 liters and a temperature of 294 K?

7.4

Explanation:

What would be the pressure, in atm, exerted by 3.2 moles of oxygen with a volume of 12.3 liters and a temperature of 294 K?

6.3 atm

General Formulas and Concepts:

Atomic Structure

Ideal Gas Law

Ideal Gas Law Formula: PV = nRT

Explanation:

Step 1: Define

Identify variables

[Given] n = 3.2 mol O₂

[Given] V = 12.3 L

[Given] T = 294 K

[Solve] P

Step 2: Solve for P

Step 3: Check

Follow sig figs and round. We are given 2 sig figs as our lowest.

6.27965 atm ≈ 6.3 atm

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