1.the volume of air in a mountain bicycle tire is constant. the initial pressure and temperature are 3.14 atm and 26 degrees celsius. a) as the bike is ridden friction with the road causes the tire to heat up. at what kelvin temperature will the gas in the tire have a pressure of 3.96 atm

b) explain why your answer makes sense at the particle level. use the words collisions, force, and frequency in your responde.

Explanation:

Givens

P1 = 3.14 atm

T1 = 26 + 273 = 299

P2 = 3.96

T2 = ?

Equation

P1 / T1 = P2 / T2

Solution

3.14 / 299 = 3.96 / x                   Cross multiply

3.14 x = 299 * 3.96                     Divide by 3.14

x = 299*3.96 / 3.14

x = 1184.04/3.14

x = 377.08 oK                             Take off 273 to get the degrees Centigrade.

x = 104.08 oC

Part B

If you want the temperature to increase, the relationship is a direct  one. That means as the temperature goes up, the pressure will as well. So for a bicycle, it makes sense that the volume remains constant. That makes the formula above without volume because the volume would cancel out on both sides of the equation.

So as the pressure increases, the particles making up the air begin to respond by the molecules moving faster. Temperature really is the a measurement of how fast molecules are moving. So the momentum is increasing. When the particles hit something, it is with a much greater force and that increases the apparent pressure.

right

explanation:

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa