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436.8 mmHg.

Explanation:

From the question given above, the following data were obtained:

Total pressure (Pₜ) = 0.93 atm

Pressure of N₂ (Pₙ₂) = 270 mmHg

Pressure of O₂ (Pₒ₂) =?

Next, we shall convert the total pressure to mmHg . This can be obtained as follow:

1 atm = 760 mmHg

Therefore,

0.93 atm = 0.93 × 760 mmHg / 1 atm

0.93 atm = 706.8 mmHg

Finally, we shall determine the pressure of the O₂. This can be obtained as follow:

Total pressure (Pₜ) = 706.8 mmHg

Pressure of N₂ (Pₙ₂) = 270 mmHg

Pressure of O₂ (Pₒ₂) =?

Pₜ = Pₙ₂ + Pₒ₂

706.8 = 270 + Pₒ₂

Collect like terms

706.8 – 270 = Pₒ₂

436.8 = Pₒ₂

Pₒ₂ = 436.8 mmHg

Thus, the pressure of O₂ is 436.8 mmHg

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.