Using a volumetric flask, an electronic balance, some water and some store-bought salt (NaCl), make up some 0.40 M solution and have it looked at by the instructor. Show calculations and explain how you made it:​

It decreases by 4 is your answer mark brainliest 

The answer is 5 10 15

Heat capacity = mcδtheat capacity = 2.676×10^3 j ..the heat capacity given is for 7.00 g of kcn,potassium cyanide which is equal to 0. mole of mole = mass  ÷ mr of kcn is 7  ÷ 65 =0.therefore: 0. of kcn liberates 2.676×10^3 j of heat1 mole   (2.676×10^3    ÷  0.107 )  × 1 =do the calculation to obtain 25009 j = 25kj