6. The gas in a steel cylinder is at 55 °C and a pressure of 965 mmHg. What would be the temperature, in Celsius, when the pressure is 850 mmHg?

91.4°C

Explanation:

Gay - Lussac Law => T ∝ P => T = kP => k = T/P with volume (V) and mass (n) constant.

For two different Temperature (T)-Pressure (P) conditions

k₁ = k₂ => T₁/P₁ = T₂/P₂ => T₂ = T₁(P₂/P₁)

T₁ = 55°C = (55 + 273)K = 328K      

P₁ = 965 mmHg

T₂ =  ?

P₂ = 850 mmHg

T₂ = T₁(P₂/P₁) = 328K(850 mmHg/965 mmHg) = 364K = (364 - 273)°C = 91.4°C

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.