A voltaic cell consists of an Mn/Mn2 half-cell and a Pb/Pb2 half-cell. Calculate [Pb2 ] when [Mn2 ] is 1.1 M and E cell is 0.44 V.

[Pb²⁺] = 2.31x10⁻²¹ M

Explanation:

Let's write the semi reaction for each half cell:

Pb²⁺ + 2e⁻ > Pb(s)     E° = -0.13 V

Mn²⁺ + 2e⁻ > Mn(s)     E° = -1.18 V

As we can see, the E° of Pb is higher than the E° of the Mn, thus, Pb is reducting and Mn is oxidizing:

Pb²⁺ + 2e⁻ > Pb(s)     E°₁ = -0.13 V

Mn(s) > Mn²⁺ + 2e⁻      E°₂ = +1.18 V

E° = E°₁ + E°₂

E° = -0.13 + 1.18 = 1.05 V

Now, we can use the Nerst equation which is:

E = E° - 0.059/n log([Mn²⁺] / [[Pb²⁺])

From here, we just need to replace and then, solve for the [Pb²⁺]:

0.44 = 1.05 - 0.059/2 log(1.1 / x)

0.44 - 1.05 = -0.0295 log(1.1 / x)

-0.61 / -0.0295 = log(1.1 / x)

antlog(20.678) = 1.1 /x

x = [Pb²⁺] = 1.1 / 4.76x10²⁰

Hope this helps

the answer is d : ) have a good da

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.