Now suppose that 5.6 mol of aluminum reacts with 4.4 mol of bromine. Calculate the mass of aluminum bromide that can be produced from 5.6 mol of Al. Calculate the mass of aluminum bromide that can be produced from 4.4 mol of bromine. Based off of your final answers for 1 and 2 above: The limiting reactant is . The excess reactant is . The actual amount of product produced is

nanotechnology is a powerful tool in biomaterials research as it creates numerous possibilities for the engineering of functional molecules. nano-bio refers to projected ability to incorporate biomimicry into various materials at nanoscale.  

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

16

explanation:

the marks go by 4s

i wish i could but this one is weird give me abc and i can solve it.