2Fe +3S= Fe2S3 how many grams of sulfur are involved in this reaction if 95 grams of iron are needed to react with sulfur

83 g

Explanation:

Step 1: Write the balanced equation

2 Fe + 3 S ⇒ Fe₂S₃

Step 2: Calculate the moles corresponding to 95 g of Fe

The molar mass of Fe is 55.85 g/mol.

95 g × 1 mol/55.85 g = 1.7 mol

Step 3: Calculate the moles of S needed to react with 1.7 moles of Fe

The molar ratio of Fe to S is 2:3. The moles of S needed are 3/2 × 1.7 mol = 2.6 mol

Step 4: Calculate the mass corresponding to 2.6 moles of S

The molar mass of S is 32.07 g/mol.

2.6 mol × 32.07 g/mol = 83 g

i think so it’s will be b yes i believe its

the answer is 1 i believe