If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.

i believe it is c.) 1575 j.