A 48.5 mL sample of gas in a cylinder is warmed from 18°C to 92°C.

What is its volume at the final temperature? (Assume constant pressure.)
Express your answer in milliliters to three significant figures.

60.8 mL

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information given in this question;

V1 = 48.5 mL

V2 = ?

T1 = 18°C = 18 + 273 = 291K

T2 = 92°C = 92 + 273 = 365K

Using V1/T1 = V2/T2

48.5/291 = V2/365

Cross multiply

291 × V2 = 48.5 × 365

291 V2 = 17702.5

V2 = 17702.5 ÷ 291

V2 = 60.8 mL

the atomic mass is the bottom number on the element.

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