A student has a sample of 1.42 moles of fluorine gas that is contained in a 28.1 L container at 305 K. What is the pressure of the sample?

P = 1.26 atm

Explanation:

Given that,

The number of moles, n = 1.42 mol

Volume, V = 28.1 L

Temperature, T = 305 K

We need to find the pressure of the gas. The ideal gas law is as follows :

R = 0.0821 L-atm/mol-K

Put all the values,

So, the pressure of the gas is 1.26 atm.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2