URGENT A student needs to prepare 300 mL of a 0.25 M HCl solution. Determine the process by which the student should make this from 6M HCI. The student would use 300 mL of water with 0.25 mL of 6M HCI.

The student would use 25 mL of the concentrated HCl and dilute to 300 mL with water.

The student would use 12.5 mL of 6 M HCl and dilute with 287.5 mL of water.

The student would use 0.075 L of the concentrated HCl and dilute to 300mL with water.

How many moles are equivalent to 55.5g of nano3

1.aluminum chloride (alcl3), and sodium hydroxide (naoh) can react to form aluminum hydroxide (al(oh)3) and sodium chloride (nacl).    you have 13.4 g of aluminum chloride and 10.0 g of sodium hydroxide. answer the following questions: •what is the balanced equation for this reaction? •if you use all 13.4 g of aluminum chloride, how many grams of aluminum hydroxide can be formed? work must be shown to earn credit •if you use all 10.0 g of sodium hydroxide, how many grams of aluminum hydroxide can be formed? work must be shown to earn credit •how many grams of aluminum hydroxide will actually be made?     which reagent is limiting? explain your answer.

According to coulomb's law, how would the electrical force between particles change if the product of their electrical charge increased?