8. If 400 mL of gas has a temperature of 75°C, then what would be the new volume if the temperature increased to 95°C?

We are given:

V₁ = 400 mL               T₁ = 75°c = (273+75)K = 348K

V₂ = x mL                    T₂ = 95°c = (273+95)K = 368K

Deriving Boyle's Law:

here, we can see that the volume and temperature are the only variables

from the ideal gas equation:

PV = nRT

T /V = P / nR

because P, n and R are constants, P/nR is a constant value

T / V = constant

which means that the initial and final ratio of P and T will be constant, hence:

T₁ / V₁ = T₂ / V₂, this is also known as the Charles' law. what I did above was it's derivation

Finding final volume:

plugging the given values:

348/400 = 368 / x

x = 368*400 / 348

x = 422.9 mL

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol