Determine the pH of 1.0 x 10-10M NaOH
pH=

4

Explanation:

Applying,

pH = 14-pOH Equation 1

But,

pOH = -log(OH⁻)

Where OH⁻ = Hydroxyl ion concentration of NaOH.

From the question,

Given: OH⁻ = (1×10⁻¹⁰) M

Substitute these values into equation 1

pH = 14-log((1×10⁻¹⁰)

pH = 14-10

pH = 4

Hence the pH of NaOH with a molarity of 1.0 x 10-10M = 4

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explanation:

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it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter