At a particular temperature, K = 2.0 × 10-6 for the reaction 2CO2(g) ⇌ 2CO(g) + O2(g)
In an experiment 15.95 mol of CO2 is initially placed in a 1.6 L vessel. Calculate the equilibrium concentration of O2.
Give your answer to 4 decimal places.

y = 0.037 M = [O₂]

Explanation:

Let's write the equilibrium reaction:

2CO₂ <> 2CO + O₂      K = 2x10⁻⁶

The problem states that we have initially 15.95 mol of CO₂ in a 1.6 L  vessel. With this we can determine the concentration:

M = moles / V

[CO₂] = 15.95 / 1.6 = 9.97 M

Now, we need to write an ICE chart so we can have the equilibrium concentrations:

          2CO₂ <> 2CO + O₂      K = 2x10⁻⁶

I.         9.97                     0       0

C.         -2y                  +2y     +y

E.        9.97-2y              2y      y

K = [CO]² [O₂] / [CO₂]²            Replacing we have:

2x10⁻⁶ = (2y)² (y)² / (9.97 - 2y)²      But K is <10⁻⁴ so we can neglect the substraction of 9.97 - 2y, we have then:

2x10⁻⁶ = 4y² (y) / (9.97)²

2x10⁻⁶ * (9,97)² = 4y³

y = ∛2x10⁻⁶ * (9,97)² / 4

y = 0.037 M = [O₂]

Hope this helps

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.