5). At what temperature (K) will 0.854 moles of neon gas occupy 12.3 L at 1.95
atmospheres?

338.38 K

Explanation:

Applying,

PV = nRT Equation 1

Where P = pressure, V = Volume, R = Temperature, n = number of moles, T = temperature.

Make T the subject of the equation,

T = PV/nR Equation 2

From the question,

Given: P = 1.95 atm, V = 12.3 L, n = 0.854 moles

Constant: R = 0.083 L.atm/K.mol

Substitute these values into equation 2

T = (1.95×12.3)/(0.854×0.083)

T = 338.38 K

the answer is na (sodium)