HEELLLP How many liters of hydrogen gas, at STP, are required to produce 2.50 x 1022 molecules of CH4? C + 2H2 → CH4

1.8 L

Explanation:

According to Avogadro;

1 mole of CH4 contains 6.02 * 10^23 molecules of CH4

x moles of CH4 contains 2.50 x 10^22 molecules of CH4

x = 1 * 2.50 x 10^22 molecules/ 6.02 * 10^23 molecules

x = 0.04 moles of CH4

2 moles of H2 yields 1 mole of CH4 gas

x moles of H2 gas yields  0.04 moles of CH4

x = 2 moles * 0.04 moles / 1mole = 0.08 moles of H2

x = 0.08 moles of H2

Since 1 mole of H2 occupies 22.4 L

0.08 moles of H2 occupies 0.08 moles * 22.4 L/ 1 mole

= 1.8 L

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it