The decomposition of potassium chlorate, KClO3, is used as a source of oxygen in labs. How many moles of potassium chlorate are needed to produce 6.83 moles of oxygen gas?

Reaction takes place is

2KClO3 --> 2KCl + 3O2

from above equation 2 moles of potassium chlorate is forming 3 moles of Oxygen gas.

now given 6.83 moles of oxygen and moles of potassium chlorate is missing,

consider x moles of potassium chlorate are needed to form 6.83 moles of oxygen

from above condition, .

3 》》》》2

x 》》》》6.83

3/x = 2/6.83

x = 3×6.83/2

x= 10.245

Answer- 10.245 moles of potassium chlorate are needed to produce 6.83 moles of oxygen gas.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be