URGENT A 2.00 g marshmallow is combusted under a flask containing 50.0 g of water at an initial temperature of 25.0°C. After the combustion of the marshmallow, 0.30g of charred marshmallow remained and the temperature of the water increased to 75.0°C. If the energy associated by the combustion of the marshmallow is 2.5 kilocalories. What is the percent error if the packaging label says that there are 3.5 kilocalories per gram of marshmallow.

Specific heat of water is 4.184 J/g °C or 1 cal/g°C

Percent Error = 100 x (Accepted value - Experimental value)/Accepted value

A. 42% error

B. 58% error

C. 64% error

D. 29% error

Tolerance to high levels of salinity

Given data,temperature, t = 230°c = 503 kconsider the chemical reaction,ch₃oh(l) + 1/2 o₂(g)  → ch₂o(g) + h₂o(l)calculate the enthalpy change for the reaction: δh⁰rxn =  σnδh⁰f(products) -  σmδh⁰f(reactants)substitute the values from the table: δh⁰rxn = { -115.9 + (-285.8)} - {0+(-238.7)}              = -163.0 kjcalculate the entropy change for the reaction.δs⁰rxn = (219 + 70) - (127.2 + 1/2 x 205.2) = 59.2 j/kconsider the expression for free energy: δg⁰rxn =  δh⁰rxn - t  δs⁰rxnsubstitute the values in the above equationδg⁰rxn = -163 x 10³ - (503 x 59.2)              = -192777.6 j              = -192.777 kj