Calculate what the specific heat capacity of an unknown metal is if 394) of heat were released when 15.0 grams of the substance at 96.0°C was
cooled to 28.0°C?
Formula Reminders
q = mCAT
q = mHvap
q = mHfus
1. 4.01 J/gºC
2. 5910 J/g°C
3. 0.387 J/g°C

The specific heat capacity of an unknown metal is .

Explanation:

Given: Heat energy = 394 J

Mass = 15 g

Initial temperature =

Final temperature =

Formula used is as follows.

where,

q = heat energy

m = mass of substance

C = specific heat capacity

= initial temperature

= final temperature

Substitute the values into above formula as follows.

Thus, we can conclude that the specific heat capacity of an unknown metal is .

answer; i believe that the correct answer is (a) potassium(k)

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.