Use the equation: C3H8(g) + 5O2(g) → 3C02 + 4H2O(I)

How many grams of water are produced from burning 52 grams of C3H8(g)?

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

6.4 cm (max) - 25 cm (min)

answer:

technetium is the most reactive. this is followed by silver. the least reactive out of these three elements is strontium.