Consider the following chemical reaction: 4 Al(s) + 3 O2(g) ⟶2 Al2O3(s)

If 4.2 grams of Al reacts with 3.0 grams of O2,

1. How many grams of Al2O3 could be produced?

2. Which reactant is limiting?

3. Which reactant is excess?

4. How much of the excess reactant would remain?

Because you ate playdough

27. =3,500,000 x 4,000 = 14,000,000,000

Answer:             1.0  × 10⁻⁵ msolution:                     as we know ph is given as,                                    ph  = -log [h⁺]and,                                    [h⁺]  =  10^-ph    (1)putting value of ph in eq. 1,                                    [h⁺]  =  10⁻⁵                                    [h⁺]  =  1.0  × 10⁻⁵ m