Use the following chemical equation for the remaining questions: 2LiBr + I2 → 2LiI + Br2
** answers should be in correct number of significant digits for 2a and 2b**
2a. 174 g LiBr is equal to how many moles of LiBr?
1 mol
1.00 mol
2.00 mol
2 mol

2b. If 812 g LiBr is added to the reaction, how many liters of Br2 will be produced?
22.40 L
52.3 L
52.27 L
22.4 L

Honors Only
2c. If 22 g LiBr produces 41 g LiI and 35 g I2 produces 45 g LiI, which reactant is the limiting reactant?
LiBr
I2
LiI
Br2

212121212121212122121212121121212122121212121212121212121n i think

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally