For the following titrations, write out the neutralization reaction and predict if the solution at the equivalence point will be acidic, basic, or neutral. 1. HF titrated with NaOH
2. HNO3 titrated with KOH
3. CH3COO- titrated with HCl

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

answer: i dont know the answer but this might

explanation:

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12 is it do you think so